(4x+5)(2x+3)=8x^2+22+15

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Solution for (4x+5)(2x+3)=8x^2+22+15 equation: 



(4x+5)(2x+3)=8x^2+22+15

We move all terms to the left:

(4x+5)(2x+3)-(8x^2+22+15)=0

We get rid of parentheses

-8x^2+(4x+5)(2x+3)-22-15=0

We multiply parentheses ..

-8x^2+(+8x^2+12x+10x+15)-22-15=0

We add all the numbers together, and all the variables

-8x^2+(+8x^2+12x+10x+15)-37=0

We get rid of parentheses

-8x^2+8x^2+12x+10x+15-37=0

We add all the numbers together, and all the variables

22x-22=0

We move all terms containing x to the left, all other terms to the right

22x=22

x=22/22

x=1

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